IT牛人博客聚合

#!/usr/bin/env python
#-*-coding: UTF-8-*-
 
import copy
 
pool = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22]
base = 48189L
dic = {}
 
def get_pool(origin):
    '''
        计算22选5的全排列'''
    result = [[]]
    length = len(origin)
    for a in range(0, length):
        #print 'b1'
        temp = []
        temp.append(origin[a])
        for b in range(a+1, length):
            temp.append(origin[b])
            for c in range(b+1, length):
                temp.append(origin[c])
                for d in range(c+1, length):
                    temp.append(origin[d])
                    for e in range(d+1, length):
                        temp.append(origin[e])
                        new_temp = copy.copy(temp)
                        result.append(new_temp)
                        #print 'a'
                        temp.remove(origin[e])
                    temp.remove(origin[d])
 
                temp.remove(origin[c])
 
            temp.remove(origin[b])
 
        temp.remove(origin[a])
 
    return result
 
def calculate(numlist):
    '''
    计算每种22选5结果组成的整数值'''
    result = 0L
    for num in numlist:
        result = result * 100L + long(num)
    return result
 
if __name__ == '__main__':
    resultlist = get_pool(pool)
    #print resultlist
    '''
    下面的for循环计算22选5全排列组成整数后，对每天抽奖人数(base)取余后，也就是每种中奖号码的可以获奖的次数'''
    for numlist in resultlist:
        current = calculate(numlist)
        re = str(current % base + 1)
        if re not in dic:
            dic[re] = 1
        else:
            dic[re] = dic[re] + 1
 
    #这个是打印所有可能
    '''for key, value in dic.items():
        print '%s = %d' % (key, value)'''
 
    #下面是打印某种可能的概率以及最多可能的次数，还有多少个
    result = 0L
    max = 0
    cnt = 0
    '''for a in dic.values():
        if a > max:
            max = a
        if a == 5:
            cnt = cnt + 1
        result = result + a
 
    print dic['33828'] * 100.0 / result
    print max
    print cnt'''
 
    #下面打印特定序号
    if '33828' in dic:
        print '33828 = %d' % dic['33828']
    if '47015' in dic:
        print '47015 = %d' % dic['47015']